Theory

The frequencies are $f_{min} + j\,\Delta f$ up to $f_{max}$ , equation (1). When $f_{max}$ is not on that grid it is appended as the last point, so the sweep always ends exactly at $f_{max}$ , equation (2).

Each frequency costs one solve, so the cost of the sweep is proportional to the number of frequencies (Number of frequencies). The transmission loss of a muffler has sharp notches and peaks (resonances of chambers and tubes); a step much coarser than their width misses or misplaces them.

Equations

f_j = f_{min} + j\,\Delta f, \qquad j = 0, \ldots, \left\lfloor \frac{f_{max} - f_{min}}{\Delta f} \right\rfloor

(1)

\text{if } f_{last} < f_{max}:\ \text{append } f_{max}

(2)

where	meaning	unit
$\Delta f$	Frequency step (this setting)	Hz
$f_{min}, f_{max}$	Lowest and highest frequency	Hz
$f_{last}$	Last grid frequency	Hz

Default and rule

Default: 5 Hz
Rule: 5 Hz.
Source: The frequency list is the program's own construction.

Valid range > 0; linear spacing only

Values

Above 0. Shown for linear spacing only.

Theory

Equations

Default and rule

Valid range > 0; linear spacing only

Related 4